x^3의 계수가 1인 삼차식 P(x)에 대하여 P(1)=1, P(2)=3, P(3)=5일때, P(x)를 x-4로 나눌때 나머지를 구하시오
For the cubic expression P(x) where the coefficient of x^3 is 1, when P(1)=1, P(2)=3, P(3)=5, when P(x) is divided by x-4, the remainder calculate P(1),P(2),P(3) increased to 1,3,5 -> 2x-1 P(x)=Q(x)+2x+1 where Q(x) must be divided by (x-1), (x-2), (x-3) (must have it as an argument) However, since it is a cubic formula, it can be expressed as a product of (x-1), (x-2), (x-3). P(1),P(2),P(3)이 1,3..
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